3 Change title (remove "question" from title) to make it more specific

# Change in internal energy questionof a gas upon expansion against a constant external pressure

2 formatting

I have a question about the following problem which I got wrong:

During expansion of its volume from 1.00 L$$\mathrm{1.00\,L}$$ to 10.00 L$$\mathrm{10.00\,L}$$ against a constant external pressure of 2.00 atm$$\mathrm{2.00\,atm}$$, a gas absorbs 200 J$$\mathrm{200\,J}$$ of energy as heat. Calculate the change in internal energy of the gas.

First, I used the equation: change in E = q + w$$E = q + w$$. I calculated work (-P * change in V$$-P \Delta V$$) and found it to be -18 (-2 * 10 - 1) $$-18 = -2 \cdot (10 - 1)$$. Then, I added -18 to q$$-18 + q$$, the heat absorbed (200 J$$\mathrm{200\,J}$$). This gave me a result of -182 J$$\mathrm{-182\,J}$$, which is wrong by a large factor. My textbook gives the answer of -1623 J$$\mathrm{-1623\,J}$$, but I am not sure where I am going wrong...

Do you know where I made a mistake? Thank you!

I have a question about the following problem which I got wrong:

During expansion of its volume from 1.00 L to 10.00 L against a constant external pressure of 2.00 atm, a gas absorbs 200 J of energy as heat. Calculate the change in internal energy of the gas.

First, I used the equation: change in E = q + w. I calculated work (-P * change in V) and found it to be -18 (-2 * 10 - 1). Then, I added -18 to q, the heat absorbed (200 J). This gave me a result of -182 J, which is wrong by a large factor. My textbook gives the answer of -1623 J, but I am not sure where I am going wrong...

Do you know where I made a mistake? Thank you!

I have a question about the following problem which I got wrong:

During expansion of its volume from $$\mathrm{1.00\,L}$$ to $$\mathrm{10.00\,L}$$ against a constant external pressure of $$\mathrm{2.00\,atm}$$, a gas absorbs $$\mathrm{200\,J}$$ of energy as heat. Calculate the change in internal energy of the gas.

First, I used the equation: change in $$E = q + w$$. I calculated work ($$-P \Delta V$$) and found it to be $$-18 = -2 \cdot (10 - 1)$$. Then, I added $$-18 + q$$, the heat absorbed ($$\mathrm{200\,J}$$). This gave me a result of $$\mathrm{-182\,J}$$, which is wrong by a large factor. My textbook gives the answer of $$\mathrm{-1623\,J}$$, but I am not sure where I am going wrong...

Do you know where I made a mistake? Thank you!

1

# Change in internal energy question

I have a question about the following problem which I got wrong:

During expansion of its volume from 1.00 L to 10.00 L against a constant external pressure of 2.00 atm, a gas absorbs 200 J of energy as heat. Calculate the change in internal energy of the gas.

First, I used the equation: change in E = q + w. I calculated work (-P * change in V) and found it to be -18 (-2 * 10 - 1). Then, I added -18 to q, the heat absorbed (200 J). This gave me a result of -182 J, which is wrong by a large factor. My textbook gives the answer of -1623 J, but I am not sure where I am going wrong...

Do you know where I made a mistake? Thank you!