So the question says:

If the mole fraction for $\ce{H2SO4}$ in an aqueous solution is $0.325$, what is the mass of water (in grams) in $100\ \mathrm{mL}$ of solution?

Me, and my other classmates tried to solve this one but we didn't reach a fully correct answer and our teacher arrives at a different answer.

So the question says:

If the mole fraction for $\ce{H2SO4}$ in an aqueous solution is $0.325$, what is the mass of water (in grams) in $100\ \mathrm{mL}$ of solution?

Me, and my other classmates tried to solve this one but we didn't reach a fully correct answer and our teacher arrives at a different answer.

My answer is:

Since X(H2SO4) + X(H2O) = 1

So: 1-0.325=0.675

X(H2O)=0.675

The mole percent is (0.675*100)=67.5%

1 mole percent = 0.01 mol

H2O moles = 0.675mol

H2O mass (g) = (0.675) * (18) = 12.15 g

Teacher is not convinced with this answer and say its wrong because the total must be 100g, and if the H2O mass is 12.15g then H2SO4 mass will be 31.85g, and 12.25+31.85 dont equal 100.

His answer is simple as follows:

1-0.325=0.675

0.675=67.5% of H2O

H2O mass= 67.5g

So the question says:

If the mole fraction for H2SO4 in an aqueous solution is (0.325), what is the mass of watter (by gram) in a 100 mL of solution??

Me, and my other classmates tried to solve this one but we didn't reach a 100% correct answer, even our teacher have a different answer.

Thank you.

So the question says:

If the mole fraction for $\ce{H2SO4}$ in an aqueous solution is $0.325$, what is the mass of water (in grams) in $100\ \mathrm{mL}$ of solution?

Me, and my other classmates tried to solve this one but we didn't reach a fully correct answer and our teacher arrives at a different answer.