Always remember that the difference in ionization enthalpy of two successive states is approx or equal to 10$10$ to 15 eV$\pu{15 eV}$ or less. The lower oxidation state is not stable; conversely if the difference is more than 15 eV$\pu{15 eV}$, the lower oxidation state is more stable. Here the 3rd$3^\mathrm{rd}$ and 2nd$2\mathrm{nd}$ ionization enthalpy difference is more than 15 eV;$\pu{15 eV}$; that's why second ionization enthalpy is more stable