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S Apr 2, 2017 at 18:31 history suggested Tyberius CC BY-SA 3.0
\dfrac doesn't​ render in Android app
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S Apr 2, 2017 at 18:31
Feb 23, 2017 at 17:15 vote accept Pranshu Malik
Apr 24, 2018 at 13:10
Sep 3, 2016 at 15:37 comment added MaxW I should have pointed out that the simple Coulomb's law also breaks down for the inner orbitals of heavy elements. Ab inito calculation for the inner orbitals (ie 1s) have to be corrected for relativity. So some of the gained energy appears to be converted to mass.
Sep 3, 2016 at 15:02 comment added MaxW The excess energy gets emitted as an electron neutrino. See en.wikipedia.org/wiki/Electron_capture // Reread my post. As the distance approaches zero the energy doesn't go to infinity. The proton and the electron have real volumes as particles. Also at the distance that they merge Coulomb's Law doesn't apply. Rather Coulomb's law works in the other direction. As the electron from a beta particle gets 100 atomic diameters away from the nucleus it is at essentially an infinite distance since we can measure the energy loss to 4 significant figures (I'd guess).
Sep 3, 2016 at 12:43 comment added Pranshu Malik @MaxW I understand, but when the electron is really near the nucleus and not far, we would have a really low potential energy, but the speed might exceed in such configuration which is why we don't really have anything below the 1s orbital. So when you lower your potential energy, you gain kinetic energy, but when they "collide" would they not realease some energy, understanding that the kinetic energy will approach infinity (due to relativistic corrections), so the mass would also increase, so isn't this really going weird?
Sep 3, 2016 at 9:33 comment added Ivan Neretin I'd rather underline that Coulomb's law still works at these distances; it is just that an electron is not a dot.
Sep 2, 2016 at 23:10 history answered MaxW CC BY-SA 3.0