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3 Improved formatting of reactions

Hi I know that balancing redox equations you first work out the separate half equations first and then combine them however i'mI'm not sure how to balance this one?

$$Cr_2O_7^{2-} + H^+(aq) + e^- \rightarrow Cr^{3+}(aq) + H_2O(l)$$$$\ce{Cr_2O_7^{2-} + H^+(aq) + e^- \rightarrow Cr^{3+}(aq) + H_2O(l)}$$

I've arried at $$Cr_2O_7^{2-} + 3e^- \rightarrow Cr^{3+}$$$$\ce{Cr_2O_7^{2-} + 3e^- \rightarrow Cr^{3+}}$$ however for $$H^+ \rightarrow H_2O$$ Im$$\ce{H^+ \rightarrow H_2O}$$ I'm not sure what to add because the oxidation for state of Hydrogenhydrogen is the same???

Hi I know that balancing redox equations you first work out the separate half equations first and then combine them however i'm not sure how to balance this one?

$$Cr_2O_7^{2-} + H^+(aq) + e^- \rightarrow Cr^{3+}(aq) + H_2O(l)$$

I've arried at $$Cr_2O_7^{2-} + 3e^- \rightarrow Cr^{3+}$$ however for $$H^+ \rightarrow H_2O$$ Im not sure what to add because the oxidation for state of Hydrogen is the same???

Hi I know that balancing redox equations you first work out the separate half equations first and then combine them however I'm not sure how to balance this one?

$$\ce{Cr_2O_7^{2-} + H^+(aq) + e^- \rightarrow Cr^{3+}(aq) + H_2O(l)}$$

I've arried at $$\ce{Cr_2O_7^{2-} + 3e^- \rightarrow Cr^{3+}}$$ however for $$\ce{H^+ \rightarrow H_2O}$$ I'm not sure what to add because the oxidation for state of hydrogen is the same?

2 Improved formatting of reactions

Hi I know that balancing redox equations you first work out the separate half equations first and then combine them however i'm not sure how to balance this one?

Cr2O7^2- + H^+(aq) + e -→ Cr^3+(aq) + H2O(l)$$Cr_2O_7^{2-} + H^+(aq) + e^- \rightarrow Cr^{3+}(aq) + H_2O(l)$$

I've arried at Cr2O7^2- + 3e --> Cr^3+$$Cr_2O_7^{2-} + 3e^- \rightarrow Cr^{3+}$$ however for H^+ --> H2O$$H^+ \rightarrow H_2O$$ Im not sure what to add because the oxidation for state of Hydrogen is the same???

Hi I know that balancing redox equations you first work out the separate half equations first and then combine them however i'm not sure how to balance this one?

Cr2O7^2- + H^+(aq) + e -→ Cr^3+(aq) + H2O(l)

I've arried at Cr2O7^2- + 3e --> Cr^3+ however for H^+ --> H2O Im not sure what to add because the oxidation for state of Hydrogen is the same???

Hi I know that balancing redox equations you first work out the separate half equations first and then combine them however i'm not sure how to balance this one?

$$Cr_2O_7^{2-} + H^+(aq) + e^- \rightarrow Cr^{3+}(aq) + H_2O(l)$$

I've arried at $$Cr_2O_7^{2-} + 3e^- \rightarrow Cr^{3+}$$ however for $$H^+ \rightarrow H_2O$$ Im not sure what to add because the oxidation for state of Hydrogen is the same???

1

# How could you balance this redox equation involving Cr2O7 2- and H2O

Hi I know that balancing redox equations you first work out the separate half equations first and then combine them however i'm not sure how to balance this one?

Cr2O7^2- + H^+(aq) + e -→ Cr^3+(aq) + H2O(l)

I've arried at Cr2O7^2- + 3e --> Cr^3+ however for H^+ --> H2O Im not sure what to add because the oxidation for state of Hydrogen is the same???