The degrees of unsaturation for a hydrocarbon of formula $\mathrm{C_xH_y}$ is equal to $\dfrac{(2x+2-y)}{2}$. The addition of an oxygen atom does not change the number of degrees of unsaturation, so acetone has 1 degree of unsaturation. This is confirmed by looking at acetone's structure, which contains a double bond between the carbon and the oxygen. Reacting acetone with $\ce{H2}$ will result in 2-propanol according to the reduction reaction found here, and thus, 1 mole of hydrogen should be required to convert acetone into a saturated compound.

While acetone is not a saturated compound, the degree of unsaturation comes from the carbon-oxygen bond. All of the carbon-carbon bonds on the compound are saturated, and that is probably what the teachers who said that this compound was saturated meant. Here is a link to learn more about degrees of unsaturation.

The degrees of unsaturation for a hydrocarbon of formula $\mathrm{C_xH_y}$ is equal to $\dfrac{(2x+2-y)}{2}$. The addition of an oxygen atom does not change the number of degrees of unsaturation, so acetone has 1 degree of unsaturation. This is confirmed by looking at acetone's structure, which contains a double bond between the carbon and the oxygen. Reacting acetone with $\ce{H2}$ will result in 2-propanol according to the reduction reaction found here, and thus, 1 mole of hydrogen should be required to convert acetone into a saturated compound.

While acetone is not a saturated compound according to the aforementioned criteria found from this source, the degree of unsaturation comes from the carbon-oxygen bond, meaning that within some contexts, it is considered a saturated compound. According to the wikipedia article on saturated vs. unsaturated compounds, unsaturation only counts when it is the result of double or triple carbon-carbon bonds. All of the carbon-carbon bonds on the compound in acetone are single, implying that the compound is saturated according to these criteria.

Either way, this is a poorly written question, and either answer should be considered acceptable.

The degrees of unsaturation for a hydrocarbon of formula $\ce{CxHy}$ is equal to $\dfrac{(2x+2-y)}{2}$. The addition of an oxygen atom does not change the number of degrees of unsaturation, so acetone has 1 degree of unsaturation. This is confirmed by looking at acetone's structure, which contains a double bond between the carbon and the oxygen. Reacting acetone with $\ce{H2}$ will result in 2-propanol according to the reduction reaction found here, and thus, 1 mole of hydrogen should be required to convert acetone into a saturated compound.

While acetone is not a saturated compound, the degree of unsaturation comes from the carbon-oxygen bond. All of the carbon-carbon bonds on the compound are saturated, and that is probably what the teachers who said that this compound was saturated meant. Here is a link to learn more about degrees of unsaturation.

The degrees of unsaturation for a hydrocarbon of formula $\mathrm{C_xH_y}$ is equal to $\dfrac{(2x+2-y)}{2}$. The addition of an oxygen atom does not change the number of degrees of unsaturation, so acetone has 1 degree of unsaturation. This is confirmed by looking at acetone's structure, which contains a double bond between the carbon and the oxygen. Reacting acetone with $\ce{H2}$ will result in 2-propanol according to the reduction reaction found here, and thus, 1 mole of hydrogen should be required to convert acetone into a saturated compound.

While acetone is not a saturated compound, the degree of unsaturation comes from the carbon-oxygen bond. All of the carbon-carbon bonds on the compound are saturated, and that is probably what the teachers who said that this compound was saturated meant. Here is a link to learn more about degrees of unsaturation.