Here are two different reactions in which lithium aluminium hydride, $\ce{LiAlH4}$, reduces a carbonyl group:
Why does $\ce{LiAlH4}$ completely remove the oxygen from the amide, but only reduces the carbonyl group of a ketone/aldehyde to a hydroxyl group? Is the difference due to the fact that $\ce{H2O}$ is added in the first reaction (i.e. if the aldehyde/ketone reduction had a second step where water was added, would the carbonyl group be reduced to a methylene group)?
Here are two different reactions in which lithium aluminium hydride, $\ce{LiAlH4}$, reduces a carbonyl group:
Why does $\ce{LiAlH4}$ completely remove the oxygen from the amide but only reduces the carbonyl group of a ketone/aldehyde to a hydroxyl group? Is the difference due to the fact that $\ce{H2O}$ is added in the first reaction (i.e. if the aldehyde/ketone reduction had a second step where water was added, would the carbonyl group be reduced to a methylene group)?
Here are two different reactions in which lithium aluminium hydride, $\ce{LiAlH4}$, reduces a carbonyl group:
Why does $\ce{LiAlH4}$ completely remove the oxygen from the amide, but only reduces the carbonyl group of a ketone/aldehyde to a hydroxyl group? Is the difference due to the fact that $\ce{H2O}$ is added in the first reaction (i.e. if the aldehyde/ketone reduction had a second step where water was added, would the carbonyl group be reduced to a methylene group)?
Here are two different reactions in which LiAlH4lithium aluminium hydride, $\ce{LiAlH4}$, reduces a carbonyl group:
Why does LiAlH4$\ce{LiAlH4}$ completely remove the oxygen from the N-substituted amide but only reduces the carbonyl to a primary alcohol forgroup of a ketone/aldehyde to a hydroxyl group? Is the difference due to the fact that H2O$\ce{H2O}$ is added in the first reaction (i.e. if the aldehyde/ketone reduction had a second step where water was added, would it become R-CH2-Rthe carbonyl group be reduced to a methylene group)?
Here are two different reactions in which LiAlH4 reduces a carbonyl:
Why does LiAlH4 completely remove the oxygen from the N-substituted amide but only reduces the carbonyl to a primary alcohol for a ketone/aldehyde? Is the difference due to the fact that H2O is added in the first reaction (i.e. if the aldehyde/ketone reduction had a second step where water was added, would it become R-CH2-R)?
Here are two different reactions in which lithium aluminium hydride, $\ce{LiAlH4}$, reduces a carbonyl group:
Why does $\ce{LiAlH4}$ completely remove the oxygen from the amide but only reduces the carbonyl group of a ketone/aldehyde to a hydroxyl group? Is the difference due to the fact that $\ce{H2O}$ is added in the first reaction (i.e. if the aldehyde/ketone reduction had a second step where water was added, would the carbonyl group be reduced to a methylene group)?
