Timeline for Using Dalton's law of partial pressure to find percentages of composition
Current License: CC BY-SA 4.0
22 events
| when toggle format | what | by | license | comment | |
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| Apr 13, 2021 at 3:56 | history | edited | Safdar Faisal | CC BY-SA 4.0 |
modified tags, spacing, title
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| Feb 27, 2016 at 13:07 | vote | accept | CommunityBot | ||
| Feb 26, 2016 at 20:32 | answer | added | LastAlchemist | timeline score: 3 | |
| Feb 26, 2016 at 17:43 | history | edited | user23923 | CC BY-SA 3.0 |
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| Feb 26, 2016 at 16:55 | comment | added | user23923 | Let us continue this discussion in chat. | |
| Feb 26, 2016 at 16:55 | history | edited | user23923 | CC BY-SA 3.0 |
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| Feb 26, 2016 at 16:53 | comment | added | user23923 | @SujithSizon Who said it is a solution? I said it is a mixture. | |
| Feb 26, 2016 at 16:52 | comment | added | Sujith Sizon | @bluebellae its a solution you have to include partial pressure of water | |
| Feb 26, 2016 at 16:50 | comment | added | user23923 | @SujithSizon Even if I had not known this formula, to calculate the weight of a substance in a compound, I would have used : (weight of that substance /total weight)* 100 using some simple maths. Why you are so fascinated by that formula? Also, we will need the total pressure, but that will be the one in the original mixture because that is what is asked. | |
| Feb 26, 2016 at 16:44 | comment | added | Sujith Sizon | @bluebellae the w/w formula is based on the "solution" of the mixture so shouldn't we take the total pressure of the solution (=745)? (Also while doing salt analysis you write O.S. instead of X solution right? ) | |
| Feb 26, 2016 at 16:40 | comment | added | user23923 | @SujithSizon We will need the w/w relation but that is not the integral part of the question. The question, according to me, is not framed to test your knowledge about this formula. | |
| Feb 26, 2016 at 16:35 | comment | added | user23923 | @SujithSizon Oh sorry, that was a mistake. I mean 745. | |
| Feb 26, 2016 at 16:32 | comment | added | Sujith Sizon | @bluebellae by 748 you mean 745 ? | |
| Feb 26, 2016 at 16:30 | comment | added | user23923 | @ChesterMiller I already mentioned it; weight percentage of Neon=34.54% and Helium=65.45% | |
| Feb 26, 2016 at 16:29 | comment | added | user23923 | @SujithSizon The question is not about simply applying the weight % formula. All I want to know is why should we take total pressure as 748 mm Hg when we are just concerned about the original mixture. The vapour pressure of water was just given to solve the first part, it should not have any relation with original mixture. | |
| Feb 26, 2016 at 12:59 | comment | added | Sujith Sizon | Weight % = 100*(weight of substance/ weight of SOLUTION),so whats your doubt? | |
| Feb 26, 2016 at 12:58 | comment | added | Chet Miller | OK. What do you get for the mole fractions of helium and neon in the original mixture (excluding the water)? | |
| Feb 26, 2016 at 12:23 | comment | added | user23923 | Sorry, I wrote hydrogen in place of neon. The question does not mention any other detail besides these, and I don't think we need any more details. Rest of the variables can be assumed as they will eventually cancel out. | |
| Feb 26, 2016 at 12:20 | history | edited | user23923 | CC BY-SA 3.0 |
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| Feb 26, 2016 at 9:33 | history | edited | M.A.R. | CC BY-SA 3.0 |
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| Feb 26, 2016 at 9:23 | review | First posts | |||
| Feb 26, 2016 at 9:33 | |||||
| Feb 26, 2016 at 9:18 | history | asked | user23923 | CC BY-SA 3.0 |