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Gaurang Tandon
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Why is Cr(2+) is a stronger reducing agent than Fe(2+) in water?

According to me, $\ce{Fe^{2+}}$ should be a better reducing agent because $\ce{Fe^2+}$ - after gettingbeing oxidized - will attain a stable $\ce{d^5}$ configuration, whereas $\ce{Cr^2+}$ will getattain a $\ce{d^3}$ configuration. I think the half filled $\ce{d^5}$ configuration is more stable than the $\ce{d^3}$ configuration. Why is this not so?

Why Cr(2+) is a stronger reducing agent than Fe(2+) in water?

According to me, $\ce{Fe^{2+}}$ should be a better reducing agent because $\ce{Fe^2+}$ after getting oxidized will attain a stable $\ce{d^5}$ configuration, whereas $\ce{Cr^2+}$ will get a $\ce{d^3}$ configuration. I think the half filled $\ce{d^5}$ configuration is more stable than the $\ce{d^3}$ configuration. Why is this not so?

Why is Cr(2+) a stronger reducing agent than Fe(2+) in water?

According to me, $\ce{Fe^{2+}}$ should be a better reducing agent because $\ce{Fe^2+}$ - after being oxidized - will attain a stable $\ce{d^5}$ configuration, whereas $\ce{Cr^2+}$ will attain a $\ce{d^3}$ configuration. I think the half filled $\ce{d^5}$ configuration is more stable than the $\ce{d^3}$ configuration. Why is this not so?

added 25 characters in body; edited title
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Gaurang Tandon
  • 9.9k
  • 12
  • 67
  • 126

Why Cr(2+) is a stronger reducing agent than Fe(2+) in water?

According to me, $\ce{Fe^{2+}}$ should be a better reducing agent because $\ce{Fe^{2+}}$$\ce{Fe^2+}$ after getting oxidized will getattain a stable $d^5$$\ce{d^5}$ configuration and, whereas $\ce{Cr^{2+}}$$\ce{Cr^2+}$ will get a $d^3$$\ce{d^3}$ configuration. I think the half filled $d^5$$\ce{d^5}$ configuration is more stable than the $d^3$$\ce{d^3}$ configuration. Why is this not so?

Why Cr(2+) stronger reducing agent than Fe(2+) in water?

According to me $\ce{Fe^{2+}}$ should be a better reducing agent because $\ce{Fe^{2+}}$ after getting oxidized will get a stable $d^5$ configuration and $\ce{Cr^{2+}}$ will get a $d^3$ configuration. I think the half filled $d^5$ configuration is more stable than the $d^3$ configuration. Why is this not so?

Why Cr(2+) is a stronger reducing agent than Fe(2+) in water?

According to me, $\ce{Fe^{2+}}$ should be a better reducing agent because $\ce{Fe^2+}$ after getting oxidized will attain a stable $\ce{d^5}$ configuration, whereas $\ce{Cr^2+}$ will get a $\ce{d^3}$ configuration. I think the half filled $\ce{d^5}$ configuration is more stable than the $\ce{d^3}$ configuration. Why is this not so?

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added 49 characters in body; edited tags; edited title
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bon
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Why Cr(+22+) stronger reducing agent than Fe(+22+) in water?

According to me Fe(+2)$\ce{Fe^{2+}}$ should be a better reducing agent because Fe(+2)$\ce{Fe^{2+}}$ after getting oxidized will get a stable d5$d^5$ configuration and Cr(+2)$\ce{Cr^{2+}}$ will get d3a $d^3$ configuration. I think the half filled d5$d^5$ configuration is more stable than d3the $d^3$ configuration. Why is is itthis not so?

Why Cr(+2) stronger reducing agent than Fe(+2) in water?

According to me Fe(+2) should be a better reducing agent because Fe(+2) after getting oxidized will get a stable d5 configuration and Cr(+2) will get d3 configuration. I think half filled d5 configuration is more stable than d3 configuration. Why is is it so?

Why Cr(2+) stronger reducing agent than Fe(2+) in water?

According to me $\ce{Fe^{2+}}$ should be a better reducing agent because $\ce{Fe^{2+}}$ after getting oxidized will get a stable $d^5$ configuration and $\ce{Cr^{2+}}$ will get a $d^3$ configuration. I think the half filled $d^5$ configuration is more stable than the $d^3$ configuration. Why is this not so?

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ketone
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