# Timeline for How does Palladium dissociate H₂ so easily?

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Jan 30, 2013 at 3:24 answer timeline score: 15
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Dec 9, 2012 at 10:56 comment @BenNorris: And presumably that the transition between the Kubas-bound state $\ce{Pd(\mu -H2)}$ and the dissociated hydride must have a very low barrier and not involve much of an energy change.
Dec 9, 2012 at 7:45 history tweeted
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Dec 7, 2012 at 16:56 comment Metallic (Interstitial) hydrides are quite well-knows, and proximity of Delta G (Free Energy) of formation for some hydride to zero is not that strange. What is much more interesting, is easiness, with which protons travels through solid palladium. This is a thing that hard to understand.
Dec 7, 2012 at 16:51 comment There is an equilibrium process, then, that can be manipulated by changing the conditions (for example low pressure vs. high pressure). I just don't know how it is done.
Dec 7, 2012 at 14:42 comment That seems a reasonable conclusion and is what I assumed until I read that Palladium hydride readily releases H₂ by the reverse process of hydrogen absorption.
Dec 7, 2012 at 12:32 comment The one-line answer would be that the two Pd-H bonds that form must be lower in energy, but right now I don't have anything to back that up.
Dec 7, 2012 at 7:39 history edited