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Nov 11, 2019 at 4:21 history protected Martin - マーチン
Jul 7, 2018 at 3:00 comment added Gaurang Tandon Related: Why are atoms with eight electrons in the outer shell extremely stable?
S Nov 12, 2016 at 13:59 comment added David Rosen So the question becomes: Why does the creation of a full outer shell for a pair of hydrogen atoms produce a low potential energy arrangement... "bonding distance"... at which there is zero force?
S Nov 12, 2016 at 13:59 comment added David Rosen I've wondered about this issue also. The answers that I've found generally use the rules of quantum chemistry as an explanation. But while these rules are consistent they don't provide the kind of explanation I and others would find more satisfying. As a starting point, it seems to me that there has to be some relationship between a full outer shell and the ability to construct a low potential energy arrangement. Using the case of a diatomic like H2 for simplicity, a low potential energy arrangement exists a the particular distance at which there is neither attracting nor repelling force.
Oct 1, 2014 at 9:59 answer added Maxistence timeline score: 3
Sep 30, 2014 at 21:42 vote accept Mertcan Ekiz
Sep 30, 2014 at 21:40 history tweeted twitter.com/#!/StackChemistry/status/517066489955115008
Sep 30, 2014 at 20:46 answer added Philipp timeline score: 18
Sep 30, 2014 at 19:04 history edited Philipp
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Sep 30, 2014 at 18:42 comment added Mertcan Ekiz Thanks, I looked into it. But it explains why the number of electrons in a specific shell's full state is what it is, not why it's more stable than the neutral state of the atom, which is what I'm asking
Sep 30, 2014 at 18:23 comment added Philipp Have a look here.
Sep 30, 2014 at 18:17 review First posts
Sep 30, 2014 at 18:45
Sep 30, 2014 at 18:14 history asked Mertcan Ekiz CC BY-SA 3.0