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Copy edited (e.g. ref. <https://www.youtube.com/watch?v=1Dax90QyXgI&t=17m54s> and <https://en.wikipedia.org/wiki/Lindlar_catalyst>). Used a more direct cross reference (as user names can change at any time).
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edit approved Aug 8, 2021 at 17:26
Peter Mortensen
edit approved Aug 8, 2021 at 17:26
Peter Mortensen
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There is just a silly mistake. As TRC toldTRC told, $\ce{Pd/C}$ is not lindlar'sa Lindlar catalyst and it behaves as a normal $\ce{Pd/H2}$  . Refer to linkthe link for more information.

There is just a silly mistake. As TRC told $\ce{Pd/C}$ is not lindlar's catalyst and it behaves as normal $\ce{Pd/H2}$  . Refer link for more information.

There is just a silly mistake. As TRC told, $\ce{Pd/C}$ is not a Lindlar catalyst and it behaves as a normal $\ce{Pd/H2}$. Refer to the link for more information.

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Jay
Jay
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There is just a silly mistake. As TRCTRC told $\ce{Pd/C}$ is not lindlar's catalyst and it behaves as normal $\ce{Pd/H2}$ . Refer link for more information.

There is just a silly mistake. As TRC told $\ce{Pd/C}$ is not lindlar's catalyst and it behaves as normal $\ce{Pd/H2}$ . Refer link for more information.

There is just a silly mistake. As TRC told $\ce{Pd/C}$ is not lindlar's catalyst and it behaves as normal $\ce{Pd/H2}$ . Refer link for more information.

Source Link
Jay
Jay
  • 802
  • 4
  • 24

There is just a silly mistake. As TRC told $\ce{Pd/C}$ is not lindlar's catalyst and it behaves as normal $\ce{Pd/H2}$ . Refer link for more information.