3 slight clean up edited Feb 23 '18 at 6:26 Gaurang Tandon 5,39277 gold badges2929 silver badges7070 bronze badges $$K_{c}$$$$K_\mathrm c$$ is defined as (for more information see here) $$\begin{equation} K_{c} = \prod_i [c_{i}]^{\nu_{i}} = \frac{\prod \limits_{i \in \text{products}} [c_{i}]^{|\nu_{i}|}}{\prod \limits_{j \in \text{reactants}} [c_{j}]^{|\nu_{j}|}} \end{equation}$$ where $$\nu_{i}$$ and $$c_{i}$$ are the stochiometric coefficient and the concentration of the $$i^{\text{th}}$$ component in the reaction, respectively. If you use this definition for the reaction $$\begin{equation} \ce{2SO2 + O2 -> 2SO3} \end{equation}$$ you get $$\begin{equation} K_{c} = \frac{[\ce{SO3}]^2}{[\ce{SO2}]^{2} [\ce{O2}]} \end{equation}$$$$\begin{equation} K_\mathrm c = \frac{[\ce{SO3}]^2}{[\ce{SO2}]^{2} [\ce{O2}]} \end{equation}$$ where the notation $$[i] = c_{i}$$ was used. This equation tells you that $$K_{c}$$$$K_\mathrm c$$ has the unit $$\begin{equation} \text{unit of }K_{c} = \frac{\left(\frac{\mathrm{mol}}{\mathrm{L}} \right)^{2}}{\left(\frac{\mathrm{mol}}{\mathrm{L}} \right)^{2} \left(\frac{\mathrm{mol}}{\mathrm{L}} \right)} = \frac{\mathrm{L}}{\mathrm{mol}} \ . \end{equation}$$$$\begin{equation} \text{unit of }K_\mathrm c = \frac{\left(\frac{\mathrm{mol}}{\mathrm{L}} \right)^{2}}{\left(\frac{\mathrm{mol}}{\mathrm{L}} \right)^{2} \left(\frac{\mathrm{mol}}{\mathrm{L}} \right)} = \frac{\mathrm{L}}{\mathrm{mol}} \ . \end{equation}$$ $$K_{c}$$ is defined as (for more information see here) $$\begin{equation} K_{c} = \prod_i [c_{i}]^{\nu_{i}} = \frac{\prod \limits_{i \in \text{products}} [c_{i}]^{|\nu_{i}|}}{\prod \limits_{j \in \text{reactants}} [c_{j}]^{|\nu_{j}|}} \end{equation}$$ where $$\nu_{i}$$ and $$c_{i}$$ are the stochiometric coefficient and the concentration of the $$i^{\text{th}}$$ component in the reaction, respectively. If you use this definition for the reaction $$\begin{equation} \ce{2SO2 + O2 -> 2SO3} \end{equation}$$ you get $$\begin{equation} K_{c} = \frac{[\ce{SO3}]^2}{[\ce{SO2}]^{2} [\ce{O2}]} \end{equation}$$ where the notation $$[i] = c_{i}$$ was used. This equation tells you that $$K_{c}$$ has the unit $$\begin{equation} \text{unit of }K_{c} = \frac{\left(\frac{\mathrm{mol}}{\mathrm{L}} \right)^{2}}{\left(\frac{\mathrm{mol}}{\mathrm{L}} \right)^{2} \left(\frac{\mathrm{mol}}{\mathrm{L}} \right)} = \frac{\mathrm{L}}{\mathrm{mol}} \ . \end{equation}$$ $$K_\mathrm c$$ is defined as (for more information see here) $$\begin{equation} K_{c} = \prod_i [c_{i}]^{\nu_{i}} = \frac{\prod \limits_{i \in \text{products}} [c_{i}]^{|\nu_{i}|}}{\prod \limits_{j \in \text{reactants}} [c_{j}]^{|\nu_{j}|}} \end{equation}$$ where $$\nu_{i}$$ and $$c_{i}$$ are the stochiometric coefficient and the concentration of the $$i^{\text{th}}$$ component in the reaction, respectively. If you use this definition for the reaction $$\begin{equation} \ce{2SO2 + O2 -> 2SO3} \end{equation}$$ you get $$\begin{equation} K_\mathrm c = \frac{[\ce{SO3}]^2}{[\ce{SO2}]^{2} [\ce{O2}]} \end{equation}$$ where the notation $$[i] = c_{i}$$ was used. This equation tells you that $$K_\mathrm c$$ has the unit $$\begin{equation} \text{unit of }K_\mathrm c = \frac{\left(\frac{\mathrm{mol}}{\mathrm{L}} \right)^{2}}{\left(\frac{\mathrm{mol}}{\mathrm{L}} \right)^{2} \left(\frac{\mathrm{mol}}{\mathrm{L}} \right)} = \frac{\mathrm{L}}{\mathrm{mol}} \ . \end{equation}$$ 2 replaced http://chemistry.stackexchange.com/ with https://chemistry.stackexchange.com/ edited Apr 13 '17 at 12:57 $$K_{c}$$ is defined as (for more information see herehere) $$\begin{equation} K_{c} = \prod_i [c_{i}]^{\nu_{i}} = \frac{\prod \limits_{i \in \text{products}} [c_{i}]^{|\nu_{i}|}}{\prod \limits_{j \in \text{reactants}} [c_{j}]^{|\nu_{j}|}} \end{equation}$$ where $$\nu_{i}$$ and $$c_{i}$$ are the stochiometric coefficient and the concentration of the $$i^{\text{th}}$$ component in the reaction, respectively. If you use this definition for the reaction $$\begin{equation} \ce{2SO2 + O2 -> 2SO3} \end{equation}$$ you get $$\begin{equation} K_{c} = \frac{[\ce{SO3}]^2}{[\ce{SO2}]^{2} [\ce{O2}]} \end{equation}$$ where the notation $$[i] = c_{i}$$ was used. This equation tells you that $$K_{c}$$ has the unit $$\begin{equation} \text{unit of }K_{c} = \frac{\left(\frac{\mathrm{mol}}{\mathrm{L}} \right)^{2}}{\left(\frac{\mathrm{mol}}{\mathrm{L}} \right)^{2} \left(\frac{\mathrm{mol}}{\mathrm{L}} \right)} = \frac{\mathrm{L}}{\mathrm{mol}} \ . \end{equation}$$ $$K_{c}$$ is defined as (for more information see here) $$\begin{equation} K_{c} = \prod_i [c_{i}]^{\nu_{i}} = \frac{\prod \limits_{i \in \text{products}} [c_{i}]^{|\nu_{i}|}}{\prod \limits_{j \in \text{reactants}} [c_{j}]^{|\nu_{j}|}} \end{equation}$$ where $$\nu_{i}$$ and $$c_{i}$$ are the stochiometric coefficient and the concentration of the $$i^{\text{th}}$$ component in the reaction, respectively. If you use this definition for the reaction $$\begin{equation} \ce{2SO2 + O2 -> 2SO3} \end{equation}$$ you get $$\begin{equation} K_{c} = \frac{[\ce{SO3}]^2}{[\ce{SO2}]^{2} [\ce{O2}]} \end{equation}$$ where the notation $$[i] = c_{i}$$ was used. This equation tells you that $$K_{c}$$ has the unit $$\begin{equation} \text{unit of }K_{c} = \frac{\left(\frac{\mathrm{mol}}{\mathrm{L}} \right)^{2}}{\left(\frac{\mathrm{mol}}{\mathrm{L}} \right)^{2} \left(\frac{\mathrm{mol}}{\mathrm{L}} \right)} = \frac{\mathrm{L}}{\mathrm{mol}} \ . \end{equation}$$ $$K_{c}$$ is defined as (for more information see here) $$\begin{equation} K_{c} = \prod_i [c_{i}]^{\nu_{i}} = \frac{\prod \limits_{i \in \text{products}} [c_{i}]^{|\nu_{i}|}}{\prod \limits_{j \in \text{reactants}} [c_{j}]^{|\nu_{j}|}} \end{equation}$$ where $$\nu_{i}$$ and $$c_{i}$$ are the stochiometric coefficient and the concentration of the $$i^{\text{th}}$$ component in the reaction, respectively. If you use this definition for the reaction $$\begin{equation} \ce{2SO2 + O2 -> 2SO3} \end{equation}$$ you get $$\begin{equation} K_{c} = \frac{[\ce{SO3}]^2}{[\ce{SO2}]^{2} [\ce{O2}]} \end{equation}$$ where the notation $$[i] = c_{i}$$ was used. This equation tells you that $$K_{c}$$ has the unit $$\begin{equation} \text{unit of }K_{c} = \frac{\left(\frac{\mathrm{mol}}{\mathrm{L}} \right)^{2}}{\left(\frac{\mathrm{mol}}{\mathrm{L}} \right)^{2} \left(\frac{\mathrm{mol}}{\mathrm{L}} \right)} = \frac{\mathrm{L}}{\mathrm{mol}} \ . \end{equation}$$ 1 answered Aug 18 '14 at 14:03 Philipp 15k22 gold badges5858 silver badges104104 bronze badges $$K_{c}$$ is defined as (for more information see here) $$\begin{equation} K_{c} = \prod_i [c_{i}]^{\nu_{i}} = \frac{\prod \limits_{i \in \text{products}} [c_{i}]^{|\nu_{i}|}}{\prod \limits_{j \in \text{reactants}} [c_{j}]^{|\nu_{j}|}} \end{equation}$$ where $$\nu_{i}$$ and $$c_{i}$$ are the stochiometric coefficient and the concentration of the $$i^{\text{th}}$$ component in the reaction, respectively. If you use this definition for the reaction $$\begin{equation} \ce{2SO2 + O2 -> 2SO3} \end{equation}$$ you get $$\begin{equation} K_{c} = \frac{[\ce{SO3}]^2}{[\ce{SO2}]^{2} [\ce{O2}]} \end{equation}$$ where the notation $$[i] = c_{i}$$ was used. This equation tells you that $$K_{c}$$ has the unit $$\begin{equation} \text{unit of }K_{c} = \frac{\left(\frac{\mathrm{mol}}{\mathrm{L}} \right)^{2}}{\left(\frac{\mathrm{mol}}{\mathrm{L}} \right)^{2} \left(\frac{\mathrm{mol}}{\mathrm{L}} \right)} = \frac{\mathrm{L}}{\mathrm{mol}} \ . \end{equation}$$