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Which compound have electrovalent, covalent, coordinate as well as hydrogen bond ?

A) $\ce{[Cu(H2O)4]SO4.H2O}$
B) $\ce{[Zn(H2O)6]SO4.H2O}$
C) $\ce{[Fe(H2O)6]SO4.H2O}$
D) $\ce{[Fe(H2O)6]Cl3}$

My approach and doubt:

All the compounds contain electrovalent, covalent as well as coordinate bonds hence the deciding factor is hydrogen bonding. (D) clearly would not have hydrogen bonding. Now my doubt is in comparison of (a),(b),(c). I know that in structure (A) in $\ce{CuSO4.5H2O}$ the fifth water of crystallisation is hydrogen bonded.

But what about (B) and (C) ? If the water molecule outside the coordinate sphere denoted by "$\ce{.H2O}$ " is not hydrogen bonded then what type of bond does it form?

Which compound have electrovalent, covalent, coordinate as well as hydrogen bond ?

A) $\ce{[Cu(H2O)4]SO4.H2O}$
B) $\ce{[Zn(H2O)6]SO4.H2O}$
C) $\ce{[Fe(H2O)6]SO4.H2O}$
D) $\ce{[Fe(H2O)6]Cl3}$

Answer given:

Option (A)

My approach

All the compounds contain electrovalent, covalent as well as coordinate bonds hence the deciding factor is hydrogen bonding. (D) clearly would not have hydrogen bonding. I know that in (A) which is $\ce{CuSO_4.5H_2O}$ the fifth $\ce{H_2O}$ which is something that was taught to me earlier.

My Doubt:
Yes I get the answer to the given mcq problem above but I was not able to understand the case of (B) and (C). I think that the $\ce{H_2O}$ inside the coordination sphere are bonded through dative bond and the $\ce{SO_4}$ outside by ionic bonds but I am not able to understand the nature of bond formed by "$\ce{.H_2O}$" present outside the main coordination sphere given in the complexes above. Would they not form hydrogen bond? The answer scheme doesn't think so. So if they don't what is the nature of bond formed by these "$\ce{.H_2O"}$ !?

Which compound have electrovalent, covalent, coordinate as well as hydrogen bond ?

A) $\ce{[Cu(H2O)4]SO4.H2O}$
B) $\ce{[Zn(H2O)6]SO4.H2O}$
C) $\ce{[Fe(H2O)6]SO4.H2O}$
D) $\ce{[Fe(H2O)6]Cl3}$

My approach and doubt:

All the compounds contain electrovalent, covalent as well as coordinate bonds hence the deciding factor is hydrogen bonding. (D) clearly would not have hydrogen bonding. Now my question doubt is in comparison of (a),(b),(c). I know that in structure (A) in $\ce{CuSO4.5H2O}$ the fifth water of crystallisation is hydrogen bonded.

But what about (B) and (C) ? If the water molecule outside the coordinate sphere denoted by "$\ce{.H2O}$ " is not hydrogen bonded then what type of bond does it form?

Which compound have electrovalent, covalent, coordinate as well as hydrogen bond ?

A) $\ce{[Cu(H2O)4]SO4.H2O}$
B) $\ce{[Zn(H2O)6]SO4.H2O}$
C) $\ce{[Fe(H2O)6]SO4.H2O}$
D) $\ce{[Fe(H2O)6]Cl3}$

My approach and doubt:

All the compounds contain electrovalent, covalent as well as coordinate bonds hence the deciding factor is hydrogen bonding. (D) clearly would not have hydrogen bonding. Now my doubt is in comparison of (a),(b),(c). I know that in structure (A) in $\ce{CuSO4.5H2O}$ the fifth water of crystallisation is hydrogen bonded.

But what about (B) and (C) ? If the water molecule outside the coordinate sphere denoted by "$\ce{.H2O}$ " is not hydrogen bonded then what type of bond does it form?

Which compound have electrovalent, covalent, coordinate as well as hydrogen bond ?

A) $\ce{[Cu(H2O)4]SO4.H2O}$
B) $\ce{[Zn(H2O)6]SO4.H2O}$
C) $\ce{[Fe(H2O)6]SO4.H2O}$
D) $\ce{[Fe(H2O)6]SO4.Cl3}$

My approach and doubt:

All the compounds contain electrovalent, covalent as well as coordinate bonds hence the deciding factor is hydrogen bonding. (D) clearly would not have hydrogen bonding. Now my question doubt is in comparison of (a),(b),(c). I know that in structure (A) in $\ce{CuSO4.5H2O}$ the fifth water of crystallisation is hydrogen bonded.

But what about (B) and (C) ? If the water molecule outside the coordinate sphere denoted by "$\ce{.H2O}$ " is not hydrogen bonded then what type of bond does it form?

Which compound have electrovalent, covalent, coordinate as well as hydrogen bond ?

A) $\ce{[Cu(H2O)4]SO4.H2O}$
B) $\ce{[Zn(H2O)6]SO4.H2O}$
C) $\ce{[Fe(H2O)6]SO4.H2O}$
D) $\ce{[Fe(H2O)6]Cl3}$

My approach and doubt:

All the compounds contain electrovalent, covalent as well as coordinate bonds hence the deciding factor is hydrogen bonding. (D) clearly would not have hydrogen bonding. Now my question doubt is in comparison of (a),(b),(c). I know that in structure (A) in $\ce{CuSO4.5H2O}$ the fifth water of crystallisation is hydrogen bonded.

But what about (B) and (C) ? If the water molecule outside the coordinate sphere denoted by "$\ce{.H2O}$ " is not hydrogen bonded then what type of bond does it form?