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Aug 10, 2014 at 13:12 comment added Jannis Andreska @K_P I was also sceptical about that 1,3-H shift, because of an apparent lack of "driving force" for this reaction step. Your suggested 1,5-H shift, which is driven by rearomatization and also leads to the acetal cation, makes much more sense. I have edited the mechanism accordingly.
Aug 10, 2014 at 13:05 history edited Jannis Andreska CC BY-SA 3.0
improved mechanism according to comment
Aug 10, 2014 at 1:03 comment added K_P In the top part I would start by pushing electrons from the furan oxygen. That gives me the same intermediate. Then I don't really like that 1,3-H shift. You can drive forward by rearomatisation and get rid of the exocyclic double bond too, so 1,5-H shift, to give a 2-methoxyfuran which is even more reactive and will open wide by the standard mechanism, starting by pushing electrons from the furan or the methoxy O and protonate the 3-position
Aug 9, 2014 at 19:14 vote accept Philipp
Aug 9, 2014 at 13:57 history answered Jannis Andreska CC BY-SA 3.0