Timeline for Balancing reaction between copper and nitric acid given the ratio of formed nitrogen oxides
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 24, 2021 at 6:58 | history | edited | Poutnik | CC BY-SA 4.0 |
added 106 characters in body
|
| Apr 21, 2021 at 17:15 | comment | added | porphyrin | This is an interesting reaction for without specifying the ratio of NO to NO2 there are essentially an infinite number of solutions. So just for interest if a 1:1 ratio is needed then the coefficients are 2 , 6 , 2 , 1, 1, 3, in the order above, a ratio of 9:1 NO:NO2 the coefficients are 14 , 38, 14, 9, 1, 19 and 1:9 are 6, 22 , 6, 1 , 9 , 11 so more nitric acid relative to Cu favours NO2 production. | |
| Apr 20, 2021 at 11:22 | history | edited | Poutnik | CC BY-SA 4.0 |
deleted 2 characters in body
|
| Apr 20, 2021 at 10:48 | history | edited | Poutnik | CC BY-SA 4.0 |
added 152 characters in body
|
| Apr 20, 2021 at 9:36 | history | edited | Poutnik | CC BY-SA 4.0 |
added 71 characters in body
|
| Apr 20, 2021 at 7:18 | comment | added | Poutnik | Always include in questions the procedure leading to the questioned result. Without it, it is hard to help. | |
| Apr 20, 2021 at 7:13 | comment | added | Rover | Thanks for detailed answer, I got where I went wrong I have $\ce{5H+}$ on LHS I.e +5e charge, but on RHS charge is 0, right ! | |
| Apr 20, 2021 at 6:56 | history | edited | Poutnik | CC BY-SA 4.0 |
added 42 characters in body
|
| Apr 20, 2021 at 6:50 | history | answered | Poutnik | CC BY-SA 4.0 |