Post Closed as "off-topic" by Mithoron, Todd Minehardt, tschoppi, Jon Custer, A.K.
2 typography corrected
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A 20 lit$20\ \mathrm l$ steel cylinder containing $N_{2(g)}$$\ce{N2(g)}$ at 20atm & 300K$20\ \mathrm{atm}$ and $300\ \mathrm K$ is kept in a big jar containing air at 1 atm & 300K$1\ \mathrm{atm}$ and $300\ \mathrm K$ and sealed. $N_{2(g)}$$\ce{N2(g)}$ starts leaking into the jar but reversibly &and isothermally. When both mechanical &and thermal equilibria are stabilized, pressure in the jar was 1.19 atm$1.19\ \mathrm{atm}$. Determine work done by $N_{2(g)}$$\ce{N2(g)}$.

Since there is mechanical equilibrium, the pressures should be equal to 1.19atm$1.19\ \mathrm{atm}$ inside and outside the cylinder with nitrogen. And since temperatures are equal too, should I use this formula for work? $W=-nRT(ln(\frac{V_{2}}{V_{1}}))$$$W=-nRT\ln\frac{V_{2}}{V_{1}}$$

A 20 lit steel cylinder containing $N_{2(g)}$ at 20atm & 300K is kept in a big jar containing air at 1 atm & 300K and sealed. $N_{2(g)}$ starts leaking into the jar but reversibly & isothermally. When both mechanical & thermal equilibria are stabilized, pressure in the jar was 1.19 atm. Determine work done by $N_{2(g)}$.

Since there is mechanical equilibrium, the pressures should be equal to 1.19atm inside and outside the cylinder with nitrogen. And since temperatures are equal too, should I use this formula for work? $W=-nRT(ln(\frac{V_{2}}{V_{1}}))$

A $20\ \mathrm l$ steel cylinder containing $\ce{N2(g)}$ at $20\ \mathrm{atm}$ and $300\ \mathrm K$ is kept in a big jar containing air at $1\ \mathrm{atm}$ and $300\ \mathrm K$ and sealed. $\ce{N2(g)}$ starts leaking into the jar but reversibly and isothermally. When both mechanical and thermal equilibria are stabilized, pressure in the jar was $1.19\ \mathrm{atm}$. Determine work done by $\ce{N2(g)}$.

Since there is mechanical equilibrium, the pressures should be equal to $1.19\ \mathrm{atm}$ inside and outside the cylinder with nitrogen. And since temperatures are equal too, should I use this formula for work? $$W=-nRT\ln\frac{V_{2}}{V_{1}}$$

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Work done by gas in isothermal process

A 20 lit steel cylinder containing $N_{2(g)}$ at 20atm & 300K is kept in a big jar containing air at 1 atm & 300K and sealed. $N_{2(g)}$ starts leaking into the jar but reversibly & isothermally. When both mechanical & thermal equilibria are stabilized, pressure in the jar was 1.19 atm. Determine work done by $N_{2(g)}$.

Since there is mechanical equilibrium, the pressures should be equal to 1.19atm inside and outside the cylinder with nitrogen. And since temperatures are equal too, should I use this formula for work? $W=-nRT(ln(\frac{V_{2}}{V_{1}}))$