Post Closed as "off-topic" by Mithoron, Todd Minehardt, tschoppi, Jon Custer, A.K.
2 typography corrected

A 20 lit$$20\ \mathrm l$$ steel cylinder containing $$N_{2(g)}$$$$\ce{N2(g)}$$ at 20atm & 300K$$20\ \mathrm{atm}$$ and $$300\ \mathrm K$$ is kept in a big jar containing air at 1 atm & 300K$$1\ \mathrm{atm}$$ and $$300\ \mathrm K$$ and sealed. $$N_{2(g)}$$$$\ce{N2(g)}$$ starts leaking into the jar but reversibly &and isothermally. When both mechanical &and thermal equilibria are stabilized, pressure in the jar was 1.19 atm$$1.19\ \mathrm{atm}$$. Determine work done by $$N_{2(g)}$$$$\ce{N2(g)}$$.

Since there is mechanical equilibrium, the pressures should be equal to 1.19atm$$1.19\ \mathrm{atm}$$ inside and outside the cylinder with nitrogen. And since temperatures are equal too, should I use this formula for work? $$W=-nRT(ln(\frac{V_{2}}{V_{1}}))$$$$W=-nRT\ln\frac{V_{2}}{V_{1}}$$

A 20 lit steel cylinder containing $$N_{2(g)}$$ at 20atm & 300K is kept in a big jar containing air at 1 atm & 300K and sealed. $$N_{2(g)}$$ starts leaking into the jar but reversibly & isothermally. When both mechanical & thermal equilibria are stabilized, pressure in the jar was 1.19 atm. Determine work done by $$N_{2(g)}$$.

Since there is mechanical equilibrium, the pressures should be equal to 1.19atm inside and outside the cylinder with nitrogen. And since temperatures are equal too, should I use this formula for work? $$W=-nRT(ln(\frac{V_{2}}{V_{1}}))$$

A $$20\ \mathrm l$$ steel cylinder containing $$\ce{N2(g)}$$ at $$20\ \mathrm{atm}$$ and $$300\ \mathrm K$$ is kept in a big jar containing air at $$1\ \mathrm{atm}$$ and $$300\ \mathrm K$$ and sealed. $$\ce{N2(g)}$$ starts leaking into the jar but reversibly and isothermally. When both mechanical and thermal equilibria are stabilized, pressure in the jar was $$1.19\ \mathrm{atm}$$. Determine work done by $$\ce{N2(g)}$$.

Since there is mechanical equilibrium, the pressures should be equal to $$1.19\ \mathrm{atm}$$ inside and outside the cylinder with nitrogen. And since temperatures are equal too, should I use this formula for work? $$W=-nRT\ln\frac{V_{2}}{V_{1}}$$

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# Work done by gas in isothermal process

A 20 lit steel cylinder containing $$N_{2(g)}$$ at 20atm & 300K is kept in a big jar containing air at 1 atm & 300K and sealed. $$N_{2(g)}$$ starts leaking into the jar but reversibly & isothermally. When both mechanical & thermal equilibria are stabilized, pressure in the jar was 1.19 atm. Determine work done by $$N_{2(g)}$$.

Since there is mechanical equilibrium, the pressures should be equal to 1.19atm inside and outside the cylinder with nitrogen. And since temperatures are equal too, should I use this formula for work? $$W=-nRT(ln(\frac{V_{2}}{V_{1}}))$$