The following is mentioned in NCERT (government textbook in India used in all schools) under chemical properties of $\ce{H2O2}:$
(iv) Reducing action in basic medium
$$\ce{I2 + H2O2 + 2 OH- -> 2 I- + 2 H2O + O2}$$
I feel the reaction is not correct. Since $\ce{H2O2}$ is a moderate/strong oxidizing agent, I don't think it can be oxidized by iodine and the reverse reaction should be true since $\ce{O2}$ is a strong oxidising agent and $\ce{I-}$ is a reducing agent. Can someone please verify it?