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Is there a positive radical Aurous, $\ce{{Au}^{x+}}$? If yes what is the value of x?

We have Auric as $\ce{{Au}^{3+}}$.

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1 Answer 1

Aurous would appear to denote Gold(I), that is, $x=+1$, as detailed on this site, which gives a profile of Gold(I) chemistry. This atom is not a radical.

Google is your friend.

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@ Richard: You mean AuCl (Aurous Chloride) does not dissociate in to ${Au}^{+}$ and ${Cl}^{-}$. – Rajesh K Singh Feb 20 '13 at 12:42
@RajeshKSingh - AuCl probably does dissociate to some degree. However, Richard means that it is not a radical in the sense that it does not have unpaired electrons. The electron configuration of Au(I) is $[\ce{Xe}]4f^{14} 5d^{10} $, which consists only of closed shells, i.e. no unpaired electrons. – Ben Norris Feb 21 '13 at 12:56
You can definitely make gold radical cations in a mass spectrometer... – J. LS Feb 27 at 11:56

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