I am trying to figure out why highly unstable cyclic boron compounds could be stabilised by two electron reduction...
My thoughts are because each Boron has an empty p-orbital perpendicular to plane of cyclic compound, pi-orbitals can form like diagrams below.
The two electrons would then go into the pi-bonding orbital, thus stabilising the entire compound.
Is this the correct explanation? If so, how can vibrational spectroscopy be useful in examining the bonding in the dianion?