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In order to prepare for a lab I need to figure out how to dilute a $.05M$ solution of Cu$^{2+}$ to $.00005M$ using the given equipment:

2 x 2.00mL graduated pipette
2 x 50.00mL volumetric flask

"You will need to dilute the .05M solution using both volumetric flasks and serial dilutions to obtain the .00005M solution."

I'm having difficulty finding a procedure to produce the desired concentration.

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1 Answer 1

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  1. Use the formula N1V1 = N2V2

  2. Take 2.00mL of 0.05M solution using pipette and make to mark in 50.00mL volumetric flask. Final concentration = 0.002M

  3. Take 1.25mL of this 0.002M solution using pipette and make to mark in 50.00mL volumetric flask. Final concentration = 0.00005M

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for questions tagged homework, you should only provide the approach to the answer, but not the complete answer. –  Ben Norris Nov 28 '12 at 11:25
    
I didn't realize I could obtain less than 2.00mL using the pipette. I guess that's why it's "graduated". I was thinking way too hard. Thanks –  Chris A Nov 28 '12 at 17:00

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