Take the 2-minute tour ×
Chemistry Stack Exchange is a question and answer site for scientists, academics, teachers and students. It's 100% free, no registration required.

In order to prepare for a lab I need to figure out how to dilute a $.05M$ solution of Cu$^{2+}$ to $.00005M$ using the given equipment:

2 x 2.00mL graduated pipette
2 x 50.00mL volumetric flask

"You will need to dilute the .05M solution using both volumetric flasks and serial dilutions to obtain the .00005M solution."

I'm having difficulty finding a procedure to produce the desired concentration.

share|improve this question

closed as off-topic by Loong, ron, Klaus Warzecha, Geoff Hutchison, Philipp Mar 5 at 23:05

This question appears to be off-topic. The users who voted to close gave this specific reason:

If this question can be reworded to fit the rules in the help center, please edit the question.

1 Answer 1

up vote 0 down vote accepted
  1. Use the formula $c_1V_1 = c_2V_2$

  2. Take 2.00 ml of 0.05 M solution using pipette and make to mark in 50.00 ml volumetric flask. Final concentration = 0.002 M

  3. Take 1.25 ml of this 0.002 M solution using pipette and make to mark in 50.00 ml volumetric flask. Final concentration = 0.00005 M

share|improve this answer
1  
for questions tagged homework, you should only provide the approach to the answer, but not the complete answer. –  Ben Norris Nov 28 '12 at 11:25
    
I didn't realize I could obtain less than 2.00mL using the pipette. I guess that's why it's "graduated". I was thinking way too hard. Thanks –  Chris A Nov 28 '12 at 17:00

Not the answer you're looking for? Browse other questions tagged or ask your own question.