# Converting percentage to molarity [closed]

I have 1 mL of saccharose and 8 mL of buffer solution, the saccharose solution has a concentration of 15% weight/volume.

Using the formula $C_1 V_1 = C_2 V_2$ I got $C_2$ which is the saccharose concentration, so the percentage is 1.66%, but I do not know how to convert this 1.66% to molarity (μmol/mL)

v1= initial volume
c1= initial concentration
v2= final volume
c2= final concentration


Can you please tell the procedure to convert this percentage to μmol/mL

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 You need to know the density of saccharose (g/mL or g/cm^3), which will let you convert the volume into a mass, and then mass into molarity. I'd write a full answer, but it is 1 am here and I'd make a really embarrassing mistake (If I haven't already) – Canageek Oct 31 '12 at 4:44 @Canageek, It would be very useful if you can give out this solution – cMinor Oct 31 '12 at 5:14 @cMinor We don't give out full solutions here, only hints for homework-y problems. There's very little conceptual matter in this question, and you've already gotten a good enough hint, so I'm closing this. Please try to ask questions with conceptual matter in the future.. – ManishEarth♦ Oct 31 '12 at 7:25

## closed as too localized by ManishEarth♦Oct 31 '12 at 7:26

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