Take the 2-minute tour ×
Chemistry Stack Exchange is a question and answer site for scientists, academics, teachers and students. It's 100% free, no registration required.

For this question, assume all things not mentioned are perfectly controlled, all at 14.7lbs of atmospheric pressure, and water is 100% pure of anything not mentioned, with no dissolved air.

Given a quantity of water that is 1 liter at 20°, what would the volume be when heated to 30°?

Secondly, the same question, except the water being heated is fully saturated with salt.

share|improve this question

2 Answers 2

up vote 7 down vote accepted

The volumetric expansion of a liquid is given by the following equation $$\ce{\Delta V = V_o~ \beta~ \Delta T}$$ where $\ce{\beta}$ is the coefficient of thermal expansion and $\ce{\Delta T}$ is the change in temperature in degrees K.

Here's a link to a nice table containing coefficients of expansion for water, both pure and salinated. Wikipedia shows the maximum solubility of salt in water to be around 36% (w/w)

From the first link we find that

$\ce{\beta}$ for pure water at $\ce{25^{o}C~ =~ 257*10^{-6}/^{o}K }$

$\ce{\beta}$ for water with 35% $\ce{NaCl}$ dissolved at $\ce{25^{o} C~ =~ 297*10^{-6}/^{o}K }$

Now you should be able to calculate the values you are interested in.

share|improve this answer
1  
Thanks so much. This is very interesting. For whatever reason, this morning I came up with a theory that perhaps more of the see rise we are experiencing is due to expansion than is due to new water in the oceans. Immediately after asking this question, I Googled and found that this theory is nothing new, and that expansion might actually account for 70% of sea rise. –  orokusaki Aug 25 at 15:24
1  
You're welcome, and nice thinking! –  ron Aug 25 at 15:29

So did you try to find any information to address this question at all?

For a starting point I would suggest http://web.mit.edu/seawater/Seawater_Property_Tables.pdf although this will not help much on the 'saturated' end of things since the salinity values in the tables do not reach the 20C saturation values. I leave finding the saturation value to the requester, since google brings it up quite easily.

share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.