"Both Vanadium and its 3+ ion are paramagnetic. Use electron configuration to explain why this is so"
The electron configuration of Vanadium is [Ar] 4s2 3d3.
If drawn in a box diagram, it would be shown that the electron in the $d$ orbitals aren't paired. This explains how an uncharged Vanadium is paramagnetic, but if Vandium loses 3 electrons, the only shells left are ones with paired electrons.
How can a Vanadium 3+ ion be paramagnetic if it loses all its unpaired electrons?