7
$\begingroup$

I've worked out five different conformations of propyl propanoate:

enter image description here

I think the bisected conformations (E) should be the most stable one.

Are my rationals and suggestions in my scheme correct?

$\endgroup$
1
  • 3
    $\begingroup$ Your basic arguments seem fine to me. Certainly the s-trans conformations are higher energy than the s-cis conformations (like E), see here for a nice explanation. As to whether B or E is favored, I think they are very close in energy, but if I had to pick just one, then I'd choose E. A few minor points, 1) there are 8 expected low-energy conformations, you've only drawn 5, 2) stereochemistry in the ethyl group is not properly displayed in C and D (you show both a methyl and a hydrogen in the plane), but I understand what you mean. $\endgroup$
    – ron
    Jun 23, 2015 at 21:57

0

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Browse other questions tagged or ask your own question.