Calculate the $\Delta H$ of the reaction where $2.6\:\mathrm{g}$ of water, $C_\mathrm{s}= 4.184 \mathrm{\frac{J}{g\:K}}$ is heated, raising the temperature increases from $298\:\mathrm{K}$ to $303\:\mathrm{K}$.
I used the following equation: $\Delta H=mC_\mathrm{s}\Delta T$
$m = 2.6~\mathrm{g}$, $C_\mathrm{s} = 4.184~\mathrm{J/g}$, $\Delta T= 5$
What I got: $(2.6)(4.184)(5)= 54.392~\mathrm{J/g}$
Did I solve this correctly?